return true

a657241074

String类
System.out.println(userLst.size());
Iterator<User> it = userLst.iterator();
while(it.hasNext()){
User u = it.next();
System.out.println(u.getId()+"---"+u.getName());
}
User类


算法1：掏出用户有权限跟不决义权限的内容
有个条件对象必需笼罩：
SELECT *
  FROM content a  -- 内容表(内容ID)
WHERE (EXISTS (SELECT 1
                  FROM privilige b  -- 权限表(内容ID,用户ID)
                 WHERE a.content_id = b.contentid
                   AND a.content_type_id = :1
                   AND b.userid = :2) OR NOT EXISTS
        (SELECT 1 FROM privilige b WHERE a.content_id = b.contentid))
   AND a.content_type_id = :1
这几天作名目研讨出来了多少个算法，给大家分享：
// 覆盖equals
public boolean equals(Object user){
  if(((User)user).getId().equals(this.getId())){
   return true;
  }else{
   return false;
  }
}

  // 覆盖hashCode  
  public int hashCode() {  
      int result;  
      result = this.id.hashCode() + this.id.toLowerCase().hashCode();  
      return result;  
  }  

User[] users = {new User("111A","张三"),
  new User("111a","张三"),
  new User("111","李四"),
  new User("222","王麻子")};
HashSet<User> hs = new HashSet<User>(Arrays.asList(users));
List<User> userLst = new ArrayList<User>(hs);
String[] aaa = {"aaa","bbb","aaa","ccc"};
List<String> src = Arrays.asList(aaa);
HashSet hs = new HashSet(src);
List<String> rslt = new ArrayList<String>(hs);
算法2：Java对象排重